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Ellipsoidal and Cartesian Coordinates Conversion: Difference between revisions
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The <math>(x,y,z)</math> ECEF cartesian coordinates can be expressed in the ellipsoidal coordinates <math>(\ | The <math>(x,y,z)</math> ECEF cartesian coordinates can be expressed in the ellipsoidal coordinates <math>(\varphi, \lambda, h)</math>, where <math>\varphi</math> and <math>\lambda</math> are, respectively, the latitude and longitude from the ellipsoid, and <math>h</math> the height above it. Figure 1 illustrates the relation between Cartesian and ellipsoidal coordinates. | ||
Figure 1 | ::[[File:Ellipsoidal_&_Cartesian_Coord_Conv.png|none|thumb|640px|'''''Figure 1: Cartesian <math>(x,y,z)</math> and ellipsoidal <math>(\varphi, \lambda, h)</math> coordinates]] | ||
== From Ellipsoidal to Cartesian coordinates == | |||
== From | |||
The Cartesian coordinates of a point <math>(x,y,z)</math> can be obtained from the ellipsoidal coordinates <math>(\varphi, \lambda, h)</math> by the next expressions: | The Cartesian coordinates of a point <math>(x,y,z)</math> can be obtained from the ellipsoidal coordinates <math>(\varphi, \lambda, h)</math> by the next expressions: | ||
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and where the eccentricity <math>e</math> is related with the semi-major axis <math>a</math>, the semi-minor axis <math>b</math> and the flattening factor <math>f</math> by: | and where the eccentricity <math>e</math> is related with the semi-major axis <math>a</math>, the semi-minor axis <math>b</math> and the flattening factor <math>f = 1 -\frac{b}{a} </math> by: | ||
:<math> | :<math> | ||
e^2=\displaystyle \frac{a^2-b^2}{a^2}=2f- | e^2=\displaystyle \frac{a^2-b^2}{a^2}=2f-f^2 | ||
\qquad \mbox{(3)} | \qquad \mbox{(3)} | ||
</math> | </math> | ||
== From Cartesian to | == From Cartesian to Ellipsoidal coordinates == | ||
The ellipsoidal coordinates of a point <math>(\varphi, \lambda, h)</math> can be obtained from the cartesian coordinates <math>(x,y,z)</math> as follows: | The ellipsoidal coordinates of a point <math>(\varphi, \lambda, h)</math> can be obtained from the cartesian coordinates <math>(x,y,z)</math> as follows: | ||
The longitude <math>\lambda</math> is given by: | The longitude <math>\lambda</math> is given by: | ||
<math> | <math> | ||
\lambda= | \lambda= arctan2(y,x) | ||
\qquad \mbox{(4)} | \qquad \mbox{(4)} | ||
</math> | </math> | ||
Latest revision as of 13:38, 25 October 2024
| Fundamentals | |
|---|---|
| Title | Ellipsoidal and Cartesian Coordinates Conversion |
| Author(s) | J. Sanz Subirana, J.M. Juan Zornoza and M. Hernández-Pajares, Technical University of Catalonia, Spain. |
| Level | Advanced |
| Year of Publication | 2011 |
The [math]\displaystyle{ (x,y,z) }[/math] ECEF cartesian coordinates can be expressed in the ellipsoidal coordinates [math]\displaystyle{ (\varphi, \lambda, h) }[/math], where [math]\displaystyle{ \varphi }[/math] and [math]\displaystyle{ \lambda }[/math] are, respectively, the latitude and longitude from the ellipsoid, and [math]\displaystyle{ h }[/math] the height above it. Figure 1 illustrates the relation between Cartesian and ellipsoidal coordinates.
From Ellipsoidal to Cartesian coordinates
The Cartesian coordinates of a point [math]\displaystyle{ (x,y,z) }[/math] can be obtained from the ellipsoidal coordinates [math]\displaystyle{ (\varphi, \lambda, h) }[/math] by the next expressions:
- [math]\displaystyle{ \begin{array}{l} x=(N+h) \cos \varphi\,\cos \lambda\\ y=(N+h)\cos \varphi\,\sin \lambda\\ z=\left ((1-e^2)N+h \right)\sin \varphi\\ \end{array} \qquad \mbox{(1)} }[/math]
where [math]\displaystyle{ N }[/math] is the radius of curvature in the prime vertical:
- [math]\displaystyle{ N=\displaystyle \frac{a}{\sqrt{1-e^2\sin^2\varphi}} \qquad \mbox{(2)} }[/math]
and where the eccentricity [math]\displaystyle{ e }[/math] is related with the semi-major axis [math]\displaystyle{ a }[/math], the semi-minor axis [math]\displaystyle{ b }[/math] and the flattening factor [math]\displaystyle{ f = 1 -\frac{b}{a} }[/math] by:
- [math]\displaystyle{ e^2=\displaystyle \frac{a^2-b^2}{a^2}=2f-f^2 \qquad \mbox{(3)} }[/math]
From Cartesian to Ellipsoidal coordinates
The ellipsoidal coordinates of a point [math]\displaystyle{ (\varphi, \lambda, h) }[/math] can be obtained from the cartesian coordinates [math]\displaystyle{ (x,y,z) }[/math] as follows:
The longitude [math]\displaystyle{ \lambda }[/math] is given by: [math]\displaystyle{ \lambda= arctan2(y,x) \qquad \mbox{(4)} }[/math]
The latitude is computed by an iterative procedure.
- 1. The initial value is given by:
- [math]\displaystyle{ \varphi_{(0)}=\arctan\left [ \frac{z}{(1-e^2)\,p} \right ] \qquad \mbox{(5)} }[/math]
- with [math]\displaystyle{ p=\sqrt{x^2+y^2} }[/math].
- 2. Improved values of [math]\displaystyle{ \varphi }[/math], as well as the height [math]\displaystyle{ h }[/math], are computed iterating in the equations:
- [math]\displaystyle{ \begin{array}{l} N_{{(i)}}= \frac{a}{\sqrt{1-e^2\sin^2\varphi_{_{(i-1)}}}}\\[0.6cm] h_{{(i)}}=\frac{p}{\cos \varphi_{_{(i-1)}}}-N_{(i)}\\[0.5cm] \varphi_{{(i)}}= \arctan\left [ \frac{z}{ \left ( 1 - e^2\frac{N_{(i)}}{N_{(i)}+h_{(i)}} \right ) p } \right ] \end{array} \qquad \mbox{(6)} }[/math]
- The iterations are repeated until the change between two successive values of [math]\displaystyle{ \varphi_{(i)} }[/math] are smaller than the precision required.